Question

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Answer 1

64g of
`\bold{CH_(3)OH => 44.8L }`

vapour density of
`\small{\sf{CH_(3)3OH=(mass)/(volume) of } \bold{CH_(3)OH}}`

=64/44.8=10/7=1.43 g/l

Vapour density of
`\bold{CH_(3)OH = 1.43 g/L}`

Answer 2

64g of
`\bold{CH_(3)OH}\dashrightarrow`44.8L

vapour density of
`CH_(3)3OH=(mass)/(volume)` of
`\bold{CH_(3)OH}`

=64/44.8=10/7=1.43 g/l

Vapour density of
`\bold{CH_(3)OH}`=1.43g/l