Final answer:
Part Three consists of 3/10 of the novel's total pages, after calculating the fractions for Part One and Part Two and subtracting their sum from the whole.
Step-by-step explanation:
The question involves finding the fraction of the novel's total number of pages that Part three consists of, given the fractions for Part One and Part Two. We are told that Part One is 2/5 of the novel, and Part Two is 3/4 of Part One. To find the fraction for Part Three, we calculate the number of pages in Part Two by multiplying 2/5 (the fraction of Part One) by 3/4 (the fraction that Part Two is of Part One). Then, we subtract the sum of Part One and Part Two from the whole to determine Part Three's fraction of the novel.
Let the total number of pages in the novel be represented by T. So, Part One is (2/5)T, and Part Two is (3/4)(2/5)T. After simplifying Part Two's fraction, we subtract both parts from the whole (1 or T) and get Part Three's fraction.
Part Two's pages: (3/4)(2/5)T = (6/20)T = (3/10)T
Total of Part One and Part Two: (2/5)T + (3/10)T = (4/10)T + (3/10)T = (7/10)T
Therefore, Part Three consists of 1 - (7/10)T of the novel's total pages, which simplifies to 3/10 of the novel.