Question

A 18 g ball is swung at a 1m long string.It revolves every 1 s,what is the magnitude of swing's tension?

Answer 1

The magnitude of swing's tension is 0.71 N.

Step-by-step explanation:

Given;

mass of the ball, m = 18 g = 0.018 kg

angular speed of the ball, ω = 1 rev/s

radius of the motion, r = 1 m

Angular speed in rad/s is calculated as follows;

`\omega = (2\pi \ rad)/(rev) * (1 \ rev)/(s) \\\\\omega = 2 \pi \ rad/s`

Linear speed of the ball, v;

v = ωr

v = 2π x 1

v = 2π m/s

The magnitude of swing's tension is calculated as the centripetal force keeping the ball in circular motion.

`F_c =T = (mv^2)/(r) \\\\T= (0.018 \ * (2\pi )^2)/(1) \\\\T = 0.71 \ N`

Therefore, the magnitude of swing's tension is 0.71 N.