Determine the number of atoms of O in 60.1 moles of Fe₂(SO₃)₃.

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4 votes

Answer:

3.310308*10^26

Step-by-step explanation:

nO=9nFe2(SO3)3=9*60.1=540.9 moles

number of atoms: 540.9*6.02*10^23

Inus Saha answered May 14, 2022

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