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10 votes
What is the x-intercept of the graph of the function f(x) = x2 − 16x + 64?

(−8, 0)
(0, 8)
(8, 0)
(0, −8)

User Esu
by
2.8k points

2 Answers

27 votes
27 votes

Answer:

8,0

edge 20201

User Tuanvt
by
2.5k points
9 votes
9 votes

Answer:

(8,0)

Explanation:

f(x) = x^2 − 16x + 64

The x intercepts ( or zeros) are found by setting y=0

0 = x^2 − 16x + 64

Factor

0 = (x-8)(x-8)

Using the zero product property

x-8 =0 x-8 =0

x=8 x=8

(8,0)

User Jvdm
by
2.8k points