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A coin is dropped in a 15.0 m deep well.

A)How long does it take the coin to hit the surface of the water?

User Zulakis
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1 Answer

5 votes

Answer:

About 1.75 seconds

Step-by-step explanation:

We use the kinematic equation for free fall under the action of gravity:


h(t)=h_i -(1)/(2) g\,t^2\\0 = 15-(1)/(2) 9.8\,t^2\\t^2=(15*2)/(9.8) \\t=\sqrt{(15*2)/(9.8)} \\t\approx 1.75\,\,sec

User Marimaf
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