Question

what is an equation of the line the passes through the point -8,0 and is parallel to the line x+2y=14

Answer 1

y = -
`(1)/(2)`x - 4

Explanation:

If a line is parallel then it has the same slope as your original line, so solve your equation for y, 2y = -x +14, divide both sides by 2 so y = - 1/2 x + 7

So your new parallel line has a slope of -1/2, since it passes through (-8,0) now find your y-intercept, so y = -1/2 x + 7 is 0 = -1/2(-8) + b so 0 = 4 + b

so b = -4, so put it all together

y = -
`(1)/(2)`x - 4