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21 votes
Please help!!!!

CE is tangent to this circle, CD is a radius and ECB=48 what is BAC​

Please help!!!! CE is tangent to this circle, CD is a radius and ECB=48 what is BAC-example-1
User Niraj Nandane
by
2.2k points

1 Answer

10 votes
10 votes

Answer:

48degrees

Explanation:

From the circle geometry shown, traingle BDC is an isosceles triangle which shows means that their base angels are the same. Hence;

<B = <C

<CBD + <BCD + <D = 180

<BCD + <BCD + <D =180

2<BCD + <BDC = 180

Get <BCD;

<BCD+ <ECB = 90

<BCD + 48 = 90

<BCD = 90 - 48

<BCD = 42degrees

Get <BDC

2<BCD + <BDC = 180

2(42)+ <BDC = 180

84 + <BDC = 180

<BDC = 180 - 84

<BDC = 96

Since angle at the centre is twice that at the circumference, then;

<BAC = 1/2(<BDC )

<BAC = 96/2

<BAC = 48degrees

User SuperManSL
by
2.4k points
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