315,788 views
9 votes
9 votes
A baseball pitcher brings his arm forward during a pitch, rotating the forearm about the elbow. If the velocity of the ball in the pitcher's hand is 34.0 m/s and the ball is 0.310 m from the elbow joint, what is the angular velocity (in rad/s) of the forearm

User Mrc
by
2.4k points

1 Answer

17 votes
17 votes

Answer:


\omega=109.67\ rad/s

Step-by-step explanation:

Given that,

The speed of the ball, u = 34 m/s

The ball is 0.310 m from the elbow joint.

We need to find the angular velocity (in rad/s) of the forearm.

We know that,


v=r\omega\\\\\omega=(v)/(r)\\\\\omega=(34)/(0.31)\\\\\omega=109.67\ rad/s

So, the required angular velocity of the forearm is 109.67 rad/s.

User Werva
by
3.1k points