Question

a) A box contains 6 red balls, 4 white balls, and 10 black balls. Two balls are drawn at random from the box (with replacement of the first before the second is drawn). What is the probability of getting a red ball on the first draw and a white ball on the second

Answer 1

Red ball=3/10

White ball=1/5

Explanation:

Red balls=6. And all the balls are equal to 20. So probability of red ball=6/20=3/10.

White balls=4. So probability of white ball=4/20=1/5.

NB: Since the first ball was replaced, there's no need to deduct a ball from the original 20 balls.