156k views
15 votes
three odd consecutive integers are such that 3 times the smallest is 9 more than twice the largest .find the three numbers​

1 Answer

3 votes

Answer: 17, 19, 21

Explanation:

Three consecutive odd numbers: x, x+2, x+4 (since odd numbers occur every other number)

Just to show you that the numbers are x, x+2, and x+4, just say x is 13 then x+2 is 15 and x+4 is 17 (3 consecutive odd numbers)

Now the second equation:

3x = 2(x+4) + 9

three times smallest number (which is x) is equal to 2 times the largest number (x+4) plus 9

Now solve

3x = 2(x+4) +9

3x = 2x + 8 + 9

3x = 2x + 17

x = 17

x+2 = 19

x+3 = 21

User Zpalmtree
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories