Question

What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (-2, 4)?

O y=-5/2x-1
O y= -5/2x+ 5
O y=2/5x-1
O y=2/5x+5

Answer 1

`y = -(5)/(2)x-1`

Explanation:

5x + 2y = 12

2y = -5x + 12

`y = -(5)/(2)x +6`

Parallel lines have the same slope so the -5/2 remains. Just remove the b value (6) and plug in (-2,4) to the x and y spots.

`(4) = -(5)/(2)(-2) + b`

4 = 5 + b

b = -1

The new equation is
`y = -(5)/(2)x-1`