Question

What pressure is required to compress 196.0 liters of air at 1.00 atmosphere into a cylinder whose volume is 26.0 liters?

Answer 1

7.53 atm

Step-by-step explanation:

Boyle studied the relationship between the pressure of a trapped gas and its volume. The data obtained by him shows that the product of pressure and volume for the trapped air sample is constant at a constant temperature. if volume of the gas increases, its pressure decreases, and vice versa. mathematically, if the volume of the gas is V 1 and its pressure is P 1 . Let us suppose that its volume has been increased to V 2 , the as per the Boyle's law its pressure will decrease and let us assume the new pressure is P 2 . P 1 V 1 = P 2 V 2 P 1 = 1 atm V 1 = 196 L P 2 = ? V 2 = 26 L substitute the values; 1 atm x 196 L = P 2 x 26 L P 2 = 1 atm x 196 L / 26 L P 2 = 196 atm L / 26 L = 7.53 atm

Answer 2

if volume of the gas increases, its pressure decreases, and vice versa. mathematically, if the volume of the gas is

V

1

and its pressure is

P

1

. Let us suppose that its volume has been increased to

V

2

, the as per the Boyle's law its pressure will decrease and let us assume the new pressure is

P

2

.

P

1

V

1

=

P

2

V

2

P

1

= 1 atm

V

1

= 196 L

P

2

= ?

V

2

= 26 L substitute the values;

1 atm x 196 L =

P

2

x 26 L

P

2

= 1 atm x 196 L / 26 L

P

2

= 196 atm L / 26 L = 7.53 atm

Step-by-step explanation:

I hope this helps.