Answer:
Step-by-step explanation:
a) AgCl(s) in 0.025 M NaCl
Equation: AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)
Initial conc : S O O
equili conc : O S S
NaCl(s) ⇒ Na⁺ (aq) + Cl⁻ (aq)
Initial conc : 0.025 0 0
equili conc : 0 0.025 0.025
Therefore the concentration: Ag⁺ = 6.4 * 10^-9 M, Cl⁻ = 0.025 M
attached below is the detailed solution of the