Question

The equation of the line in the xy-plane that has slope 7/6 and passes through (9.-6) is

a. O 6x-7y+27 = 0
b. O 7x+6y-27 = 0
c. O 6x+7y-27=0
d. 0 6x+7 y+27 = 0
e. O -7x+6y+99 = 0
f.
No Answer

Answer 1

0 = 7x-6y -99

Explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 7/6x+b

Using the point

-6 = 7/6(9) +b

-6 = 7*3/2 +b

-6 = 21/2 +b

Subtract 21/2 from each side

-12/2 -21/2 = b

-33/2 = b

y= 7/6x -33/2

Multiply each side by 6

6y = 7x - 99

Subtract 6y from each side

0 = 7x-6y -99