Final answer:
The only possible event from the ones listed, given that the bag contains 12 green candies and 1 blue candy, is choosing 1 blue and 1 green candy.
Step-by-step explanation:
In the context of probability, the student is asking which of the listed outcomes is possible when choosing two candies from a bag containing a specific number of candies in different colors. Since the bag contains 12 green candies and 1 blue candy, there is no possibility of choosing two blue candies or two red candies, as there is only one blue candy and no red candies mentioned. Therefore, the only possible event from the ones listed is choosing 1 blue and 1 green candy.
To provide an example using similar principles, if a bag contains four green marbles, three red marbles, and two yellow marbles, and Mark draws two marbles from the bag without replacement, the probability of drawing a yellow marble and then a green marble is the probability of drawing a yellow first (2 out of 9), times the probability of drawing a green afterward (4 out of 8, since one marble has been removed and it's not green).
For another jar containing 150 jelly beans of various colors, we calculate probabilities such as P(B), P(G), P(O), etc., by dividing the number of jelly beans of a particular color by the total number of jelly beans (e.g., P(B) = 26/150).