Answer:
problems 4,5,6,7 (make sure you add °C to the answers given in step one above) *note, these answers given in both answers could be used for any of the deserts chosen, they all have the same formula given.
Explanation:
4) box 12
(12,40)
f(12)= 9/5 (40)+ 32
f(12)= 72 +32
f(12)= 104 ° F
box 24
(24, -3.2)
f(24)= 9/5 (-3.2) +32
f(24) = -5.76 +32
f(24)= 26.24 °F
5.
substitute the given C(t) equation into the conversion formula
F(t)= 9/5C(t)+32.
We know from the information given that C(t)=−0.30(t−12)^2 +32
to solve:
F(t)= 9/5[−0.30(t−12)^2+40]+32
F(t)=1.8(−0.3t^2+7.2t−3.2)+32
F(t)=−0.54t^2+12.96t−5.76+32
F(t)=−0.54t^2+12.96t+26.24
6.
on the graph plot the three points (0,-0.32), (12,104), (24,-0.32)
It draw the lines to connect the bottom two points to 12, 104, It should look like upside down V but curved softer like the graph in answer number 2.
7. The changes made to the graph of C(t) to transform it to F(t) was changing the noon temperature (plot point) from 40° C to 104° F. It increased the steepness of the graph.