Answer:
(230.21 ; 233.13)
Explanation:
Given the data :
230.66, 233.05, 232.58, 229.48, 232.58
To calculate the 90% CI
WE obtain the mean and standard deviation of the sample data :
Mean of sample, ΣX /n = 1158.35/5 = 231.67
The standard deviation of the sample, s = 1.531 (Using calculator).
(The 90% Tcritical value, 2 sided, df = 4) = 2.132
The confidence interval, CI :
Mean ± Tcritical * s/√n
C.I = 231.67 ± (2.132 * (1.531/√5)
C. I = 231.67 ± 1.4597
(231.67 - 1.4597) ; (231.67 + 1.4597)
(230.21 ; 233.13)