Answer:
D. Infinitely many solutions
Explanation:
![-(2)/(5)x-y=6 | -2x+5y=-30](https://img.qammunity.org/2022/formulas/mathematics/middle-school/hwpc15py27io02sk0f0x2271szs3bagx84.png)
1.Since neither equation contains an isolated. However, we can isolate -y in the first equation by adding
to both sides.
Like this:
![(2)/(5)x-(2)/(5)x-y=6-(2)/(5)x](https://img.qammunity.org/2022/formulas/mathematics/middle-school/hl49x3zvtc1wfbrdq0k32wr5ktqitwutcv.png)
ending up with
![y=6-(2)/(5)x](https://img.qammunity.org/2022/formulas/mathematics/middle-school/z8ftfcx8tqum6xw8x5wqwagtiav22yu890.png)
2.Now, we can change y to a positive y. By doing so, we divide -y by the entire equation.
Like this
![(-y=6-(2)/(5)x )/(-y)](https://img.qammunity.org/2022/formulas/mathematics/middle-school/h23hsstl71l4n4xmqbgqjv804oe128t6sj.png)
Ending with
![y=-6+(2)/(5)x](https://img.qammunity.org/2022/formulas/mathematics/middle-school/uftj8m8i9a5274ou964q92h2rso2fjhg4w.png)
3.Now, we can plug the expression
into the second equation as a substitute for y, and solve for x. Then, we can use x to calculate y.
Like this
![-2x+5(-6+(2)/(5)x)=-30\\ -2x-30+2x=-30\\](https://img.qammunity.org/2022/formulas/mathematics/middle-school/3w210df0r4wtlpnrkdeh00vd8vs4jn7pbf.png)
4. Since -2x+2x would cancel out and leave -30=-30. This is true because we know -30 equals -30 with no variable in sight.