Question

What is the value of mc015-1.jp g?

Answer 1

I dont know

Explanation:

Answer 2

1456

Explanation:

This question is asking us to find the sum of
`4(3)^(n-1)` from n = 1 to n = 6. We can find the sum like this:

`4(3)^(1-1) +4(3)^(2-1) +4(3)^(3-1) +4(3)^(4-1) +4(3)^(5-1) +4(3)^(6-1)`

Which can be simplified to:

`4(3)^(0) +4(3)^(1) +4(3)^(2) +4(3)^(3) +4(3)^(4) +4(3)^(5)`

`4(1) +4(3) +4(9) +4(27)+4(81) +4(243)`

`4 +12 +36 +108+324 +972 = 1456`