Answer:
Option A. 1:1
Step-by-step explanation:
From the question given above, the following data were obtained:
Li => 1s² 2s¹
Cl => 1s² 2s²2p⁶ 3s²2p⁵
Lithium (Li) will form compound with Cl by losing 1 electron as shown below:
Li —> Li⁺ + e¯ ..... (1)
Cl on the other hand will accept 1 electron from Li to form the chloride ion, Cl¯ as shown below:
Cl + e¯ —> Cl¯ ...... (2)
Combining equation 1 and 2, we have:
Li + Cl + e¯ —> Li⁺ + Cl¯ +
Cancel e¯ from both side
Li + Cl —> Li⁺Cl¯
Thus, the ratio of metallic cation (+) to non-metallic anion (-) in the compound is 1:1