Question

Find AB, BC, and BC. Round to the nearest tenth

Answer 1

i need more space to send the pic i did the math tho

Explanation:

Answer 2

The length of each segments to the nearest tenth include;

1. AB = 21.0 units.

2. BC = 45.0 units.

3. BC = 33.0 units.

In order to determine the length of segment AB, we would have to apply cosine rule (law of cosines);

`c^2 = a^2 +b^2 -2ab CosC`

Where:

a, b, and c is the length of side or side lengths of a given triangle.

Part 1.

Based on the given side lengths, we have the following:

`AB^2 = 13^2 +29^2 -2(13)(29) cos(41)\\\\ AB^2 = 169 + 841 -754cos(41)\\\\ AB^2 = 1010 -569.05\\\\AB=√(440.95)`

AB = 20.9988 ≈ 21.0 units.

Part 2.

Based on the given side lengths, we have the following:

`BC^2 = 21^2 +30^2 -2(21)(30) cos(123)\\\\ BC^2 = 441 + 900 -1260cos(123)\\\\ BC^2 = 1341 +686.2452\\\\BC=√(2027.2452)`

BC = 45.0249 ≈ 45.0 units.

Part 3.

Based on the given side lengths, we have the following:

`BC^2 = 17^2 +28^2 -2(17)(28) cos(91)\\\\ BC^2 = 289 + 784 -952cos(91)\\\\ BC^2 = 1073 +16.6147\\\\BC=√(1089.6147)`

BC = 33.0093 ≈ 33.0 units.