Question

If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?

0.0337 g

17.3 g

0.239 g

0.300 g

Answer 1

17.3 g

Step-by-step explanation:

Given the following data;

• Quantity of heat, Q = 0.507 J
• Temperature = 0.007°C
• Specific heat capacity of water = 4.2 J/g°C

Mathematically, Heat capacity is given by the formula;

`Q = MCT`

Where;

• Q represents the heat capacity or quantity of heat.
• M represents the mass of an object.
• C represents the specific heat capacity of water.
• T represents the temperature.

Making "M" the subject of formula, we have;

`M = \frac {Q}{CT}`

Substituting the values into the formula, we have;

`M = \frac {0.507}{4.2*0.007}`

`M = \frac {0.507}{0.0294}`

Mass, m = 17.3 grams