Question

What is the missing number if the mean of 48,33 is 41

Answer 1

42

Explanation:

let's make the missing number x

`mean = (sum \: of \: numbers)/(how \: many \: numbers \: there \: are)`

`41 = (48 + 33 + x)/(3)`

multiply 3 on both sides to get rid of the fraction, 41 × 3 = 123

`123 = 48 + 33 + x`

simplify the right side, 48 + 33 = 81

`123 = 81 + x`

subtract 81 on both sides

`123 - 81 = x`

`x = 42`