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25 votes
25 votes
How many moles are there in 13g of KMnO4?

RAM:

K: 39 u

Mn: 55 u

O: 16 u

User Joe Moore
by
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2 Answers

6 votes
6 votes
0.08 Moles would be your answer
User Piwo
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10 votes
10 votes

Answer:

0.08 moles

Step-by-step explanation:

Relative atomic mass of KMnO4 = K + Mn + O4 = 39 + 55 + 16 x 4 = 158

=> Moles in 13g of KMnO4 =
(Mass)/(Relative-atomic-mass) =
(13)/(158) = 0.082278.. = 0.08 moles

User Dirk Smaverson
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