Question

A plant with genotype SsYy is crossed with a plant with genotype SsYy. What is the probability

that the offspring of these plants will have smooth, yellow seeds?

Answer 1

The probability that the offspring of two plants genotypically SsYy will have smooth, yellow seeds is 56.25%, calculated by the product rule of probability as (3/4) for smooth seeds and (3/4) for yellow seeds, resulting in (3/4) × (3/4) = 9/16.

Step-by-step explanation:

The question refers to the genetic cross between two plants with the genotype SsYy. To find the probability that offspring will have smooth, yellow seeds, we need to understand the concepts of dominance and independent assortment.

Smooth seeds (S) are dominant to wrinkled seeds (s), and yellow seeds (Y) are dominant to green seeds (y). When two heterozygous plants (SsYy) are crossed, the traits for seed texture and color assort independently. Using the product rule of probability, we first calculate the probability of offspring being smooth (S) which is 3/4, since the possible combinations are SS, Ss, and sS with only ss resulting in wrinkled seeds. Similarly, the probability of offspring having a yellow seed color (Y) is also 3/4, due to the combinations YY, Yy, and yY with only yy resulting in green seeds.

Combining these two probabilities gives us the overall probability of an offspring being both smooth and yellow: (3/4) × (3/4) = 9/16. Thus, the probability that the offspring of these plants will have smooth, yellow seeds is 56.25%.

Answer 2

62.5%

Step-by-step explanation:

I posted a picture of the dihybrid cross I used to solve this below.

Both smooth seeds and yellow seeds are dominant, so any genotype with a S and a Y would have smooth, yellow seeds. 10 out of 16 on the dihybrid cross had a S and Y.
`(10)/(16)` can be simplified to
`(5)/(8)`.

To find the percentage, divide 5÷8=0.625. Multiply 0.625×100=62.5%

This means 62.5% of the offspring will have smooth yellow seeds.