Explanation:
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Answer:
Solution given:
L.H.S
sin²A-cos²B
sin²A=1-cos²A and Cos²B=1-sin²B
replacing value
1-cos²A-(1-sin²B)
1-cos²A-1+sin²B
1-1+sin²B-Cos²A
=sin²B-Cos²A
R.H.S
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