163,503 views
17 votes
17 votes
Jane , peter and mary each have some cards of 3:5:6 . Peter has 40 cards . How many fewer cards did mary has then peter?

User Saurabh Sinha
by
2.5k points

1 Answer

21 votes
21 votes

Answer:

Mary has 8 more card than Peter

Explanation:

Jane: peter: mary

3 5 6

Peter has 40

40/5 = 8

Multiply each by 8

Jane: peter: mary

3*8 5*8 6*8

24 40 48

We want Mary - Peter

48-40

8

Mary has 8 more card than Peter

User Ug
by
3.0k points
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