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What is the value of x if e^3x+6 =8? Answer:

User Traker
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2 Answers

9 votes
9 votes

Answer:

x = 1/3 ln(2) or approximately 0.23104

Explanation:

e^3x+6 =8

Subtract 6 from each side

e^3x+6-6 =8-6

e^3x =2

Take the natural log of each side

ln( e^3x) =ln(2)

3x = ln(2)

divide by 3

3x/3 = 1/3 ln(2)

x = 1/3 ln(2)

x is approximately 0.23104

User Bibo
by
2.8k points
11 votes
11 votes

Answer:


\displaystyle x = (ln2)/(3)

General Formulas and Concepts:

Pre-Algebra

  • Equality Properties

Algebra II

  • Natural logarithms ln and Euler's number e
  • Logarithmic Property [Exponential]:
    \displaystyle log(a^b) = b \cdot log(a)
  • Solving logarithmic equations

Explanation:

Step 1: Define

Identify


\displaystyle e^(3x) + 6 = 8

Step 2: Solve for x

  1. [Equality Property] Isolate x term:
    \displaystyle e^(3x) = 2
  2. [Equality Property] ln both sides:
    \displaystyle lne^(3x) = ln2
  3. Rewrite [Logarithmic Property - Exponential]:
    \displaystyle 3xlne = ln2
  4. Simplify:
    \displaystyle 3x = ln2
  5. [Equality Property] Isolate x:
    \displaystyle x = (ln2)/(3)
User Vdi
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