Answer:
Perimeter = 60
Explanation:
because l bisects AB:
3y+1 = 5y-5
reduce:
2y = 6
y = 3
and:
2x+4 = 4x-12
reduce:
2x = 16
x = 8
AB = (3y+1) + (5y-5)
AB = 8y-4
substitute for y
AB = 8(3)-4
AB = 20
Perimeter = (2x+4) + (4x-12) + 20
reduce:
perimeter = 6x+12
substitute for x:
Perimeter =6(8)+12
reduce:
Perimeter = 60