Question

Find the equation of the straight line passing through the point (0, -1) which is perpendicular to the line y=-3/4 x-3

Answer 1

y =
`(4)/(3)` x - 1

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = -
`(3)/(4)` x - 3 ← is in slope- intercept form

with slope m = -
`(3)/(4)`

Give the slope of a line m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(-(3)/(4) )` =
`(4)/(3)`

The line crosses the y- axis at (0, - 1 ) ⇒ c = - 1

y =
`(4)/(3)` x - 1 ← equation of perpendicular line