Question

A balloon filled with helium has a volume of 30.0 L at a pressure of 100 kPa and a temperature of 15.0 C. What will the volume of the balloon be if the temperature is increased to 80.0 C and the pressure remains constant? (Hint: Use the Charles law equation)

Answer 1

The final volume of the balloon is 24.480 liters.

Step-by-step explanation:

Let consider that no leakages occur in the balloon during the isobaric process and that helium behaves ideally. From Equation of State for Ideal Gases, we construct the following relationship:

`V_(o)\cdot T_(o) = V_(f)\cdot T_(f)` (1)

Where:

`V_(o)`,
`V_(f)` - Initial and final volume, measured in liters.

`T_(o)`,
`T_(f)` - Initial and final temperature, measured in Kelvin.

If we know that
`V_(o) = 30\,L`,
`T_(o) = 288.15\,K` and
`T_(f) = 353.13\,K`, the final volume of the balloon is:

`V_(f) = (V_(o)\cdot T_(o))/(T_(f))`

`V_(f) = 24.480\,L`

The final volume of the balloon is 24.480 liters.