Question

In a basketball tournament, Team A scored 5 fewer than twice as many points as Team B. Team C scored 80 more points than Team B. The combined score for all three teams was 983 points. Write an equation to represent this scenario using the variable b to represent Team B's total points. Translate the scenario.

Answer 1

(2b - 5) + b + (b + 80) = 983

Explanation:

Given that,

Total score of three teams = 983

Since the teams' scores are given in reference to team B's score, let 'b' be the score of team B.

So,

The scores of Team A = (2 * b) - 5

The scores of Team B = b

The scores of Team C = (b + 80)

Thus,

The equation for determining the total points of Team B would be:

(2b - 5) + b + (b + 80) = 983

On solving,

(2b - 5) + b + (b + 80) = 983

⇒ 2b + b + b = 983 + 5 - 80

⇒ 4b = 908

⇒ b = 908 ÷ 4

⇒ b = 227

Team B's score = 227

Team A's score = (2 * 227 - 5)

= 449

Team C's score = 227 + 80

= 307

Total ⇒ 449 + 227 + 307 = 983

Hence proved.