Question

In ABC, b = 68 inches, B=65° and C=93º. Find the length of a, to the nearest
inches

Answer 1

28inches

Explanation:

∠A + ∠B + ∠C = 180°

∠A + 65° +93° = 180°

∠A + 158° = 180°

∠A= 180°-158° = 22°

Using Law of Sines

a/sinA= b/sinB

a/sin22= 68 inches/sin65

a/sin22 = 68/0.9063 = 75.03

a = 75.03 x sin 22

a = 75.03 x 0.3746 = 28.106238≈28 inches