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At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume

be if the temperature were changed to 22 C and the pressure to 1.25 atmospheres?

User Itaydafna
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1 Answer

15 votes
15 votes

Answer: Volume would be 196.15 mL if the temperature were changed to
22^(o)C and the pressure to 1.25 atmospheres.

Step-by-step explanation:

Given:
T_(1) = 35^(o)C = (35 + 273) K = 308 K,
V_(1) = 256 mL,


P_(1) = 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm


T_(1) = 22^(o)C = (22 + 273) K = 295 K,
P_(2) = 1.25 atm

Formula used to calculate volume is as follows.


(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))

Substitute the values into above formula as follows.


(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))\\(1 atm * 256 mL)/(308 K) = (1.25 atm * V_(2))/(295 K)\\V_(2) = 196.15 mL

Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to
22^(o)C and the pressure to 1.25 atmospheres.

User Whastupduck
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