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The first stage type of rocket used in Moon missions provides an unbalanced upward force of 30MN and burns for 2.5 minutes.

a) Calculate the increase in momentum that results from the equation F=(mv-mu)/t

b) If the rocket has a mass of 3000 tonnes what is the velocity of the rocket after the first stage has completed its 'burn'?

User Jesse Jashinsky
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2 Answers

24 votes
24 votes

Final answer:

The increase in momentum can be calculated using the formula F=(mv-mu)/t, and the velocity of the rocket after the first stage burn is 1.5 m/s.

Step-by-step explanation:

To calculate the increase in momentum, we can use the formula:

F = (mv - mu) / t

Where:

F is the upward force of the rocket (30MN),

m is the mass of the rocket (3000 tonnes or 3,000,000 kg),

v is the final velocity of the rocket (unknown),

u is the initial velocity of the rocket (0 m/s),

and t is the burn time of the rocket (2.5 minutes or 150 seconds).

Plugging in these values, we can find the increase in momentum. Then, using the equation:

p = mv

We can calculate the velocity of the rocket after the first stage burn.

Let's do the calculations:

F = (mv - mu) / t

30MN = (3,000,000v - 0) / 150

30MN * 150 = 3,000,000v

4,500,000N = 3,000,000v

v = 4,500,000N / 3,000,000

v = 1.5 m/s

Therefore, the velocity of the rocket after the first stage burn is 1.5 m/s.

User Shreyas Menon
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9 votes
9 votes

Answer:jj

Explanation:hh

User Molly Harper
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