Question

Stephen rolls a fair dice 78 times. How many times would Stephen expect to roll a number greater than 2?

Answer 1

52 times

Explanation:

Given

`n = 78` -- Number of times

Required

Determine the expected times to get > 2.

In a fair dice, the outcome > 2 are:

`>2 = \{3,4,5,6\}`

The probability of the above is:

`p = (4)/(6)`

`p = (2)/(3)`

The number of times is calculated using:

`E(x) = n * p`

`E(x) = 78* (2)/(3)`

`E(x) = (78* 2)/(3)`

`E(x) = (156)/(3)`

`E(x) = 52`