Stephen rolls a fair dice 78 times. How many times would Stephen expect to roll a number greater than 2?

Question

asked Feb 26, 2022 59.2k views

1 Answer

Torie · Answer 1 · 2022-03-03T21:47:13+0000

Answer:

52 times

Explanation:

Given

n = 78 -- Number of times

Required

Determine the expected times to get > 2.

In a fair dice, the outcome > 2 are:

$>2 = \{3,4,5,6\}$

The probability of the above is:

p = (4)/(6)

p = (2)/(3)

The number of times is calculated using:

E(x) = n * p

E(x) = 78* (2)/(3)

E(x) = (78* 2)/(3)

E(x) = (156)/(3)

E(x) = 52