Question

Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.​

Answer 1

`8x^(-10)y^6 - 2x^2y^(-8) = (8y^(14) - 2x^(12))/(x^(10)y^8)`

Explanation:

Given

`8x^(-10)y^6 - 2x^2y^(-8)`

Required

Simplify

Rewrite as:

`8x^(-10)y^6 - 2x^2y^(-8) = (8y^6)/(x^(10)) - (2x^2)/(y^8)`

Take LCM

`8x^(-10)y^6 - 2x^2y^(-8) = (8y^6*y^8 - 2x^2 * x^(10))/(x^(10)y^8)`

Apply law of indices

`8x^(-10)y^6 - 2x^2y^(-8) = (8y^(14) - 2x^(12))/(x^(10)y^8)`