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Two organisms, AABBCCDDEE and aabbccddee, are mated to produce an F1 that is self-fertilized. If all of these genes are on the same chromosome, and there is no recombination, how many different genotypes will occur in the F2

User Francesco Galletta
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1 Answer

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21 votes

Answer:

2 genotypes: AABBCCDDEE; aabbccddee

Step-by-step explanation:

The law of segregation (also called Mendel's First Law) describes how genes on different chromosomes segregate into gametes independently of each other. Moreover, recombination (also known as crossing over) is the interchange of genetic material between non-sister chromatids during meiosis. In this case, the five genes are on the same chromosome (i.e., they are linked together and do not segregate) and there is no recombination, thereby they are inherited as a haplotype block to the next generation:

- Genotypes parental (P) lines: AABBCCDDEE; aabbccddee

- Cross P1: ABCDE X abcde

- Genotype F1: AaBbCcDdEe (100%)

- Gametes F1: ABCDE; abcde

- Genotypes F2: AABBCCDDEE; aabbccddee (ratio 1:1)

User Boruch
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