Answer:
1.) the y intercept is 490 and the slope is -2/3x2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right3.) f(x)= -2/3x+490The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470. 4.) graph down below5.) the profits are the same (slope) but the y intercept is higher then the original graph.6.) y=-2/3x+300
Explanation:
some of these are part of the problem as well.1.) 2x+3y=1,470 3y=-2x+1,470-2x+1,470/3-2/3x + 490y=-2/3x + 490the y intercept is 490 and the slope is -2/3x2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right3.) f(x)= -2/3x+490The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470. 5.) 2x+3y=1,5933y=-2x+1,593y=-2/3x+531the profits are the same (slope) but the y intercept is higher then the original graph.6.) (150, 200) (300, 100)y intercept= 300m= 100-200/300-150 = -100/150 = -2/3y=-2/3x+300