Question

Does anybody know this ... dang ...

Answer 1

Answer: (6, -6)

Explanation:

so midpoint =(
`(X1+X2)/(2)`,
`(Y1+Y2)/(2)`)

for x co ordinate

`(-2+X2)/(2)`=2

-2+X=4 (X2=x co ordinate point for b, can be written as just x now)

X=6

x co ordinate of B= 6

y co ordinates of y

`(-8+Y2)/(2)`=-7

-8+Y=-14

Y=-6

co ordinates B (6,-6)

for proof/extra explanation (NOT necessary for working):

`(Y1+Y2)/(2)`

=
`((-2)+6, (-8)+(-6))/(2)`

=
`(4, -14)/(2)`

=(2,-7)

which is the midpoint M