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For the function g(x) =10 x ^5/x-2, what is the inverse function?

For the function g(x) =10 x ^5/x-2, what is the inverse function?-example-1
User Yang
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1 Answer

3 votes

Answer:


g^(-1)(x) =((x)/(10))^(5) +2

Explanation:

So we have the function
g(x)=10\sqrt[5]{x-2}. To find the inverse, we first set the function equal to y:


y=10\sqrt[5]{x-2}

Then, we switch all the y and x variables, like this:


x=10\sqrt[5]{y-2}

Now, we solve for y to find the inverse function:


x=10\sqrt[5]{y-2}


(x)/(10) =\sqrt[5]{y-2}


((x)/(10))^(5) =y-2


((x)/(10))^(5) +2=y


y=((x)/(10))^(5) +2


g^(-1)(x) =((x)/(10))^(5) +2

User Jrsm
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