Question

1) (30 pts ) Oxygen (O2) flows through a pipe, entering at at 4 m/sec at 10000 kPa, 227oC. For a pipe inside diameter of 3.0 cm, find the volumetric flow rate (m3/sec) and the mass flow rate of the gas (kg/sec) assuming you have an ideal gas

Answer 1

Complete Question

Nitrogen (N2) flows through a pipe, entering at at 4 m/sec at 1000 kPa, 2270C. For a pipe inside diameter of 3 cm, find the volumetric flow rate (m3/sec) and the mass flow rate of the gas (kg/sec) assuming you have an ideal gas Then using your ideal gas mass flow rate find the rate at which enthalpy enters the pipe (kJ/sec) NO Cp, Cv, k permitted

Answer:

`H=9.91kJ/sec`

Step-by-step explanation:

From the question we are told that:

Velocity
`v=4 m/sec`

Pressure
`P=1000kPa`

Temperature
`T=227 \textdegree C`

Diameter
`d=3cm=>0.03m`

Generally the equation for volumetric Flow Rate is mathematically given by

`V_r=((\pi*d^2)/(4)v)`

`V_r=((\pi*(0.03)^2)/(4) *4)`

`V_r=0.002827m^3/s`

Generally the equation for mass Flow Rate is mathematically given by

`m_r=(PV_r)/(RT)`

`m_r=(1000*0.002827)/(0.297*(227+273))`

`m_r=0.019kg/sec`

Generally the equation for mass Flow Rate is mathematically given by

Using gas Table for enthalpy Value

`T=500K=>h=520.75kg`

Therefore

`H=mh`

`H=0.019*520.75`

`H=9.91kJ/sec`