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17 votes
17 votes
There is a pile of 55 coins consisting of nickels and dimes worth $3.90. Find the number of each if you say that the nickels are x.

User KABoissonneault
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2 Answers

18 votes
18 votes

Answer:

There are 32 nickels and 23 dimes.

Explanation:

Yay :) we solved the problem together :)))))

User MarAja
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3.2k points
14 votes
14 votes

Answer:

There are 32 nickels and 23 dimes.

Explanation:

Lets say x is nickels and y is dimes

The first equation would be 55 = x + y

The second equation would be .05x + .10y = 3.90

The Solving Part:

Move y to the other side: x = 55 - y

Substitute x in the second equation: .05(55-y) + .10y = 3.90

Distribute, rearrange, and combine like terms: .05y = 1.15

Solve for y: Y = 23

Plug in 23 for y and solve: 55 - y = x ; 55 - 23 = x ; 55 - 23 = 32

x = 32

y = 23

32 nickels and 23 dimes

User Ken Block
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2.6k points