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1 vote
1 vote
The work of a student to solve a set of equations is shown:

Equation A: y = 15 − 2z
Equation B: 2y = 3 − 4z


Step 1: −2(y) = −2(15 − 2z) [Equation A is multiplied by −2.]
2y = 3 − 4z [Equation B]
Step 2: −2y = 15 − 2z [Equation A in Step 1 is simplified.]
2y = 3 − 4z [Equation B]
Step 3: 0 = 18 − 6z [Equations in Step 2 are added.]
Step 4: 6z = 18
Step 5: z = 3


In which step did the student first make an error?
Step1
Step 2
Step 3
Step 4

User Hansy
by
2.9k points

2 Answers

25 votes
25 votes
the student made a error in step 2.
User Marquise
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3.0k points
17 votes
17 votes

Step 2

−2y = 15 − 2z

should be

−2y = -30 + 4a

User Kirt Carson
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3.2k points