Question

The Gallup Poll reported that 56% of Americans want to lose weight. If 7 people are selected at random, find the probability that they all want to lose weight. Please round the final answer to 2 or 3 decimal places.

Answer 1

`P(7)=0.0172`

Explanation:

From the question we are told that:

Sample size
`n = 7`

Probability of Event
`P(x)=56\%`

Therefore

`P(7)=^nC_x*P^n*(1-P)^0`

`P(7)=^7C_(7)*(0.56)^7*(1-(0.56))^0`

`P(7)=0.0172`