Answer:
a) 4c+3b=11.67
8c+b=12.89
b)One loaf of bread cost $2.09
One can of soup costs $1.35
Explanation:
Let c= can of soups Let b= loaf of bread
a) To find the equation, you know that Khalil buys four cans of soup and 3 loafs of bread and 4 cans of soup for $11.67 so that means that the first equation will be 4c+3b=11.67. Then, you know that Khalil buys 8 cans of soup and one bread for $12.89. so the next equation will be 8c+b=12.89. This means the system of linear equations will be
4c+3b=11.67
8c+b=12.89
b) Use elimination to solve this. You want to make one variable from each equation the same so multiply 4c+3b=11.67 by 2. This will look like 2(4c+3b=11.67). Then simplify to get 8c+6b=23.34 and 8c+b=12.89. Because 8 and 8 are the same, you have to subtract the equations from each other making 5b=10.45. Simplify that and you get b= 2.09 so the one loaf of bread cost $2.09. Then plug 2.09 into 8c+b=12.89. It will look like this 8c+2.09=12.89. Simplify that and you get 8c=10.8. Simplify that again and you will get 1.35 so a can of soup will costs $1.35
Therefore
a) 4c+3b=11.67
8c+b=12.89
b) One loaf of bread cost $2.09
One can of soup costs $1.35