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How do I Determine whether Rollie's theorem can be applied to F on the closed interval (AB) F of X = -x squared

User Evelyne
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Answer:

See Explanation

Explanation:

Your question is incomplete. I will take the complete question as:


f(x) = -x^2


Interval: [-1,1]

Required

Determine whether Rollie's theorem can be applied or not

First, find the coordinates of the endpoints on the closed interval [-1, 1]


f(x) = -x^2


f(-1) = -(-1)^2 = -1 ------
(-1,-1)


f(1) = -(1)^2 =-1 ----
(1,-1)

Find the derivative of f(x)


f(x) = -x^2


f'(x) = -2x

Calculate the slope (m) of the secant line i.e.
(-1,-1) and
(1,-1)


m = (-1 - (-1))/(1 - (-1))


m = (-1 +1)/(1 +1)


m = (0)/(2)


m=0

Set the derivative to the calculated slope:


f'(x) = m


-2x = 0


x=0

Plug in 0 for x in f'(0)


f'(x) = -2x


f'(0) = -2 * 0


f'(0) = 0

Since f'(0) is differentiable at x = 0. We can conclude that Rollie's theorem can be applied

User Tiagosilva
by
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