Question

Solve the quadratic equation
give your answer to 2 decimal places
: 3x^2+x-5=0

Answer 1

Given:

The quadratic equation is:

`3x^2+x-5=0`

To find:

The solution for the given equation rounded to 2 decimal places.

Solution:

Quadratic formula: If a quadratic equation is
`ax^2+bx+c=0`, then:

`x=(-b\pm √(b^2-4ac))/(2a)`

We have,

`3x^2+x-5=0`

Here,
`a=3,b=1,c=-5`. Using the quadratic formula, we get

`x=(-1\pm √(1^2-4(3)(-5)))/(2(3))`

`x=(-1\pm √(1+60))/(6)`

`x=(-1\pm √(61))/(6)`

`x=(-1\pm 7.81025)/(6)`

Now,

`x=(-1+7.81025)/(6)`

`x=1.13504167`

`x\approx 1.14`

And

`x=(-1-7.81025)/(6)`

`x=-1.468375`

`x\approx -1.47`

Therefore, the required solutions are 1.14 and -1.47.