Answer:
4th option and 3rd option
Explanation:
Using the recursive rule and a₁ = 7 , then
a₂ = 3a₁ - 6 = (3 × 7) - 6 = 21 - 6 = 15
a₃ = 3a₂ - 6 = (3 × 15) - 6 = 45 - 6 = 39
a₄ = 3a₃ - 6 = (3 × 39) - 6 = 117 - 6 = 111
a₅ = 3a₄ - 6 = (3 × 111) - 6 = 333 - 6 = 327
The first 5 terms are 7, 15, 39, 111, 327
---------------------------------------------------------------------
Similarly using the recursive rule and a₁ = 9
a₂ = 3a₁ + 3 = (3 × 9) + 3 = 27 + 3 = 30
a₃ = 3a₂ + 3 = (3 × 30) + 3 = 90 + 3 = 93
a₄ = 3a₃ + 3 = (3 × 93) + 3 = 279 + 3 = 282
a₅ = 3a₄ + 3 = (3 × 282) + 3 = 846 + 3 = 849
The first 5 terms are 9, 30, 93, 282, 849